So, does the TYCHOS model stand up to scrutiny, all the way to the famed ca. 25,000-26,000 year period known as the “precession of the equinoxes” *a.k.a.* “The Great Year”? Let us first verify whether the TYCHOS model can adequately explain the celestial mechanics of our nearby planets, moons and their geometrical spatial interactions over a full, so-called “Great Year”.

We know that Mars has a distinct 32-year cycle, returning to almost the same celestial place in 32 years, along with Venus, Mercury and our Moon. However, every 32 years, Mars is observed to advance (or “process”) by a tiny amount. On average this amount is by ca. 10.909 minutes of RA (Right Ascension) as longer samples of multiple 32-year periods reveal. For instance, in 352 years (32y X 11), Mars will advance by 120 min. of RA.

We may envision and define this processional motion as the secular (“long term”) processional drift of Mars’s orbital motion around our system.

Our full, 360° celestial sphere is divided in 1440 minutes. Since 1440 equals 360 X 4, Mars processes every 32 years by:

So, how many 32-year-periods will the orbital “rose” pattern of Mars need in order to complete a “full processional lapping” of itself?

**4224**years (or 1,542,816 days)

Mars will employ 4224 years to complete one full, 360° lapping of its own orbital path. Let’s now see how many of their own orbits that the Sun, Mars, Venus, Mercury and the Moon will complete in 4224 years:

MARS | 1,542,816 days / 730.5 | = 2112 orbits |

SUN | 1,542,816 days / 365.25 | = 4224 orbits |

VENUS | 1,542,816 days / 584.4 | = 2640 orbits |

MERCURY | 1,542,816 days / 116.88 | = 13200 orbits |

JUPITER | 1,542,816 days / 4383 | = 352 orbits |

MOON | 1,542,816 days / 29.22 | = 52800 orbits |

As previously mentioned, the Copernically-estimated period of the so-called “precession of the equinoxes” is 25,771 years. This is the time period currently reckoned by contemporary heliocentric theory for Earth to complete its 360° equinoctial precession (*a.k.a.* “The Great Year”). So let us try and multiply our 4224-year value by 6 and see how it goes.

Why exactly by 6? I will address this further on, in Chapter 20. For now, let’s see what we obtain:

**25344**years / or 9,256,896 days

Which will correspond to:

Since Mars advances by 120 min. every 352 years, in 25,344 years (which equals 352 X 72) Mars will thus advance by:

Note that 8640 min. = 1440 min. X 6 (of course, 1440 min. represents our full, 360° celestial sphere)

**6 times,**every

**25344 years**.

If we consider that 25344 years represents a full 360° equinoctial precession, we should now be curious to find out how long it takes for Earth’s equinoctial axis to rotate (in relation to the stars) by just 1°. Here we go:

We see that **70.4** solar years (or 25713.6 days) equals precisely:

__synodic__periods of Mars (779.2 days X 33 = 25713.6 days)

It is interesting to note that in Babylonian astronomy, the “sar” cycle was an important period of 3600 years, which, when multiplied by 7.04 gets us the Tychos Great Year (TGY) length of 25344. Let us also note that 704 years (70.4 X 10) is equivalent to:

We can now compute Earth’s “equinoctial procession rate” as of the TYCHOS system. If Earth’s equinoxes process by 1° every 70.4 years, then every century (100 years) they process by:

or

5113.

In 25344 years, there are 253.44 centuries. In fact, 253.44 X 1.420

Hence, our annual “precession rate of Earth’s equinoxes” is:

### 5113.6363 / 100 = 51.136 arc seconds*

Note that 51.1

Therefore, in several ways, we arrive at the conclusion that the Great Year is a cyclical “return” for not just Earth but the entire system.

In the following chapters, we shall see that this 51.1

Henceforth I will refer to these 51.1

NOTE: Official astronomical estimates have the stars’ annual precession rate at 50.29 arcsecs and their Great Year duration at 25771 solar years. Both these values are about 1.68% “off” the TYCHOS-computed values of 51.1